1+1+2+4+8+1+6+2+3+2+8+3+8+4+9+6+2+7+0+7+7+9+1+1+0+1+1+3+1+7+1+1+5+1+2+2

its a way of writing the number "127'
these arent random
some of you might notice a pattern
1+1 is 2 so you do
1+1+2 which is 4
1+1+2+4 = 8
1+1+2+4+8 + 16

when you get to 16 break it down to single digit and add them seperately so
1+1+2+4+"1+6"
you will get 23 so

1 + 1 + 2 + 4 + 8 + 1 + 6 + "2 + 3"
repeat
i suck at explaining things

did you know 1+1+2+4+8+1+6+2+3+2+8+3+8+4+9+6+2+7+0+7+7+9+1+1+0+1+1+3+1+7+1+1+5+1+2+2 is a way of writing 127

12👍 2👎

(sqrt(cos(x))*cos(999999999999999999999999999999999999999999999999999 x)+sqrt(abs(x))-0.7)*(4-x*x)^0.01, sqrt(9-x^2), -sqrt(9-x^2) from -4.5 to 4.5

Don't try solving it, just put it into google, it makes a nice heart!

idea from some other guy
thanks

(sqrt(cos(x))*cos(999999999999999999999999999999999999999999999999999 x)+sqrt(abs(x))-0.7)*(4-x*x)^0.01, sqrt(9-x^2), -sqrt(9-x^2) from -4.5 to 4.5

393👍 14👎

(sqrt(cos(x))*cos(200 x)+sqrt(abs(x))-0.7)*(4-x*x)^0.01, sqrt(9-x^2), -sqrt(9-x^2) from -4.5 to 4.5

Don't try to solve it, LOL .
Paste it on Google and a Heart symbol will appear <3
It's a graph drawing from that expression .

Hey babe. (sqrt(cos(x))*cos(200 x)+sqrt(abs(x))-0.7)*(4-x*x)^0.01, sqrt(9-x^2), -sqrt(9-x^2) from -4.5 to 4.5 !!!

1227👍 113👎

(sqrt(cos(x))*cos(999999999999999999999999999999999999999999999999999 x)+sqrt(abs(x))-0.7)*(4-x*x)^0.01, sqrt(9-x^2), -sqrt(9-x^2) from -4.5 to 4.5

On May 15, 2020, a user known as "giant salamanders eat paint" said, "Don't try solving it, just put it into google, it makes a nice heart!

idea from some other guy
thanks
(sqrt(cos(x))*cos(999999999999999999999999999999999999999999999999999 x)+sqrt(abs(x))-0.7)*(4-x*x)^0.01, sqrt(9-x^2), -sqrt(9-x^2) from -4.5 to 4.5" Now this guy forgot to credit the original user who made this. Me. And some dude from 2011 named "Nguyen Vu Long". SO CREDIT US!

(sqrt(cos(x))*cos(999999999999999999999999999999999999999999999999999 x)+sqrt(abs(x))-0.7)*(4-x*x)^0.01, sqrt(9-x^2), -sqrt(9-x^2) from -4.5 to 4.5

Copy-paste it noobs.

56👍 14👎

(sqrt(cos(x))*cos(200 x)+sqrt(abs(x))-0.7)*(4-x*x)^0.01, sqrt(9-x^2), -sqrt(9-x^2) from -4.5 to 4.5

This was defined in 2011, and the user who defined it said to copy-paste it and something will happen...

(sqrt(cos(x))*cos(200 x)+sqrt(abs(x))-0.7)*(4-x*x)^0.01, sqrt(9-x^2), -sqrt(9-x^2) from -4.5 to 4.5 is a line of code that can be pasted into google and stuff happens.Copy-paste this: (sqrt(cos(x))*cos(200 x)+sqrt(abs(x))-0.7)*(4-x*x)^0.01, sqrt(9-x^2), -sqrt(9-x^2) from -4.5 to 4.5

96👍 38👎

(a+b)^2=a^2+2ab+b^2

The equation (a+b)² = a² + 2ab + b² is an example of the formula for squaring a binomial. When you expand (a+b)², it means you are multiplying (a+b) by itself.

To expand (a+b)², you can use the distributive property of multiplication over addition. This means you multiply each term in the first expression by each term in the second expression and then add the results.

So, when you expand (a+b)², you get:
(a+b)² = (a+b)(a+b) = a(a+b) + b(a+b) = a² + ab + ab + b² = a² + 2ab + b²

Bro- sup dude
Me- (a+b)^2=a^2+2ab+b^2

2+2=4

How do you know it's not a false thing you believe that helps you survive? Jesus christ Alex the second I called you out as a plant you HARD SPIRALED into the Jordan Peterson nonsense tower. You're spiraling HARD right now?

Hym "Because if you have 2 to apples in a bucket and you place 2 more apples into that same bucket... You not have IIII 👈 this many. You can change the term you use to represent IIII 👈 This many. You can call 'that many' 4 or four or IV or, shit, you can even call it 5! That being said, there COULD VERY WELL BE some kind of hidden mathematical principle that affects 2+2=4 in some significant way. But, it's just low hanging fruit at this point. That's year 1 stuff. We're past all that."