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Karenβs much much much older sister.
βSusieβ Man, did you meet Susie. She taught Karen everything she knows!!
3π 5π
A fat ass hoe who cheats on her no carb no fat diet and lies to her friends about it while she eats fatty food in her car, and she makes sure food at her grocery store that she buys doesnβt have fat free on it. She calls her herself a vegan and eats salad infront of her friends.
Friend 1: I saw this girl snacking on like five burgers in her car the other day
Friend 2: Omg sheβs such a Fatty Susie
4π 12π
Girl with blond hair good serves loves volleyball and is a amazing passer.
2π 2π
Bad ass, big booty bitch that radiates pink vibes.
Daaamn. Look at that Susie!
1π 3π
A mastubation apparatus constructed by male inmates out of a plastic bag, a towel and some Vaseline. The towel is wrapped in a cylindrical form and the plastic bag is used to line the inside and the vaseline is the lubricant.
I'm pissed I left my susie in my cell and i think pookie borrowed dat shit so nows i gots to throws it out!! Pookie gots crabs.
8π 27π
A rugged beautiful Japanese beast born in 1989. Can be seen tearing up the fields of ballymacady or cruising the streets of Golden. Recent reports have placed her in the city of Limerick.
Also known as the SACKMOBILE, SUZ, and Baby Agnes.
Susie
8π 62π
An abbreviation for Super-Symmetrical Quantum mechanics.
Consider a QM system with Hamiltonian H and potential V(x) such that H |Ξ¨> = E |Ξ¨>
We define a new Hamiltonian H1 in terms of potential V1(x) which is offset by the zero point energy so that:
H1 |0> = 0 ie the enegy of the ground state of H1 is zero.
We define this Hamiltonian in terms of generalized raising and lowering operators A and A dagger such that:
H1 = A_dag A = (p^2/2m) + V1(x)
A = (ip/root(2m)) + W'(x)
Where W(x) is the super potential.
The potential V1(x) can be constructed from the superpotential:
V1(x) = W'(x)^2 - (Ρ/root(2m))W"(x)
If we know the H1 ground state Ξ¨_0(x) then we can derive:
Ξ¨_0(x) ~ exp(-root(2m)W(x)/Ρ)
Which can be used to find the superpotential W(x)
From this superpotential we can derive the partnerpotential V2(x) where:
V2(x) = W'(x)^2 - (Ρ/root(2m))W"(x)
which has associated Hamiltonian H2 = A A_dag = (p^2/2m) + V2(x)
This partner potential may allow H2 to have an eigenspectrum which is easier to find. Once this is found we can go from the nth energy level of H2 to the (n+1)th level of H1 by simply applying the A_dag operator. This means we can find the first excited state of H1 by applying A_dag to the ground state of H2.
Note: I wrote this while in class and the prof was talking about some really complex shit I wasn't paying attention to so now I'm fucked for the exam next week.
But sugondese amirite?
At least we still got us a woodshed!
Guy one: Look at that physicist fuck over there doing SUSY.
Guy two: Damn straight brother I hear SUSY sucks a lot.
Guy one: Hell yeah she does!
95π 14π